SHENZHEN I/O

SHENZHEN I/O

TRIANGULAR NUMBERS
9 条留言
Cocoa 2022 年 11 月 27 日 下午 6:36 
I calculated n(n+1)/2 and got 10/324/23
HansDampf 2021 年 4 月 30 日 上午 11:04 
6/2700/13 or 14/424/31
menoslug 2019 年 6 月 5 日 下午 10:27 
12/156/19. So difficult..
Trobby 2016 年 12 月 28 日 上午 10:50 
AND THIS TRIAGONAL SIGN
ShadowCluster 2016 年 12 月 20 日 下午 7:03 
7/140/11. Found that I could get rid of a MC6 and a ROM since the sample size is so small.
Luraman 2016 年 12 月 16 日 下午 7:07 
I did it in 7/211/14 :)

I used the fact that
f(an+b) = 0.5an^2+0.5a+anb+f(b)
and hardcoded sufficiently small b values.

As long as a is even, then this works while only using integers
ShadowCluster 2016 年 12 月 14 日 上午 2:02 
Nvm got 14/225/15.
ShadowCluster 2016 年 12 月 13 日 下午 11:25 
I got 14/315/21, with linear calculation speed of 21 power per input. Had some fun since I had more space, but if I had more I think I could do better.
-ßЯҢ- CYBER PYRO 2016 年 12 月 11 日 下午 6:51 
I don't know how I knew about the Fibonacci sequence and not a similar concept like Triangular Numbers! This was fun to solve, if you'd like to see how I did it then check out my solution here: Solution

Fair warning, I did add a lot more wires than needed but a lot are redundant and only make it look neato.