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Optimizing power a little gave me 17/233/11. Have not yet optimized lines of code.
And I don't know how to solve in less than 10 lines of code
14 / 239 / 11
Nice puzzle, lots of possible solutions, lots of room for optimization
I know this has been a while but the fact is digital signals canNOT be listened to by every connected chip as a digital signal has an address bit attached which tells all but the destination chip to ignore the signal. It's like listening to a radio; only one station comes through despite the many, many stations passing by.
I've optimized for cost and I'm down to 11 324 15.
Or with less lines for one yuan more: 12 301 13.
I was able to cut out a test and only check against 2 for lighting f. With the help of an OR chip I can add 50 to everything else. -1 becomes 49 (not enough to activate OR gate) and 2 stays 2. The rest all become 50 or greater and activate the OR gate.
https://steamuserimages-a.akamaihd.net/ugc/973226782539453420/CC59574B5EFA09CD3AA2012F22A3E3F87167B6C2/
https://psteamcommunity.yuanyoumao.com/profiles/76561198348342923/screenshot/973226782539193349
In my original comment, I said I do not like how this game handles digital signals - irl a single signal can be detected and received by every capable chip that is connected within reason. You then (half a year later, I might add) start talking about analog and digital signals and how one is measured by voltage and the other by amperage (which is not true). Perhaps I could have used the simple I/O pin (it's not called P-Port), but that was not what I was talking about. Now you are just posting nonsense, the gate pin on a field-effect transistor (also not what I was talking about) only needs to be charged (positively or negatively depending on type) for electricity to flow. They are not a simple on/off switch in the way you seem to be describing them, they can also be partially open. How many volts you need to supply to the gate pin can also be looked up in datasheets. I suggest experimenting with real life electronics.
Not really. A p-doped Transistor needs 1/√2 Volts & ~50mA to switch from LOW to HIGH. So a transistor is a consumer. Its different to a Flip-Flop which works with the De Morgan's Law's and works just tough a logical flow controll. Use the P-Line instead and every device can listen to the same signal. I often use this as Clock Signal. Im also sure that the XBUS in Shenzhen is concepted to use it like pending Signals.
As I know is an analog signal just a 0%-100% (float 0.0-1.0) value from a specified constant from voltage and amperage.
Because XBUS is a digital port and the P-Port is an analog port. The difference in reality is about meassuring the voltage or the amperage. When you measure the voltage can the voltage also be measured over the complete circuit, but when you measure amperage then you measure device is a consumer and this will drop the amperage over the complete circuit to 0. So use the P-Port instead, but think about that the P-Port can not send Data Cross-Over at the same Instruction Cycle.
14-346-16 (I blame having to repeat the signal for the other controller)
very nice level btw :)