SHENZHEN I/O

SHENZHEN I/O

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X TO THE POWER OF Y
   
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2023 年 7 月 22 日 上午 2:25
2023 年 7 月 22 日 上午 3:02
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X TO THE POWER OF Y

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8 条留言
pv2b 2024 年 1 月 18 日 上午 8:13 
I was able to use Allon's hints to come up with an even better solution at 5/268/9
tricks: Jumping takes a lot of power, so don't jump, instead just let the whole program loop. Use @ to set an initial condition state.
shigawire 2024 年 1 月 14 日 上午 12:51 
Great! Thanks! First attempt: 8/623/14
Zotmeister 2023 年 10 月 12 日 上午 2:01 
Fun! My (first) solution is clearly an inferior one, but hey, it's mine: 10/1.1K/21: two MC6000s; the first takes the base and sends it to the second, then keeps the exponent for itself; the first prompts the second to iterate the multiplication as it decrements the exponent and then sends the final result when it gets to 0. The only reason I needed an MC6000 for the first chip was that I needed more lines of code for it. Time to see what others did, I'm sure I have a lot to learn. I also have an idea for my own puzzle now...
Alion 2023 年 8 月 10 日 下午 7:14 
score: 5/320/9
components: MC4000X, 200P-14
tricks: use ROM for counter , use ROM address pin for X storage , hook up both input and output to one of the pins so you can use both tricks
Cocoa 2023 年 8 月 7 日 上午 8:20 
I found a 7 / 268 / 9 solution that use a ROM to iterate and identify how many remaining steps to go
https://psteamcommunity.yuanyoumao.com/sharedfiles/filedetails/?id=3016494638
s7eph4n 2023 年 8 月 6 日 下午 2:40 
Although I also had a solution with a RAM , I thought I still need two MC's to take track of all the values. Turns out, one MC and a RAM will also do the trick.
Improved to a 7/373/13 or a 7/349/14
irokwe 2023 年 8 月 4 日 下午 2:12 
thanks!
7/427/14
very unoptimized solution that abuses RAM for iteration count
s7eph4n 2023 年 7 月 31 日 上午 4:31 
Fun little puzzle, thanks!
My first shot: 8/678/15