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Keep Talking and Nobody Explodes

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Keep Talking and Nobody Explodes >  创意工坊 > firestarter 的创意工坊 > Signals > 讨论
Signals
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Lagmeister 2018 年 10 月 20 日 下午 8:13
Bug? (Spoilers on how to solve this)
I think the module may be broken. Every single time I try and solve this, it doesn't work.

Using the most recent test of this, I had no strikes and Channel A was fig. 4 (0,1,0). flipping switches until I got to a straight line for channel B (0,0,0) I was able to determine the switches' wiring and positions with the chart below:

[S1] [S2] [S3]

[C3] [C1] [C2]
U] [-1] [ 0] [-1]
M] [ 1] [-1] [ 1]
D] [ 0] [ 1] [ 0]

using this, I set the switches to 1,1,-1 (Or M,D,U), But instead of giving me Fig. 15 (1,1,-1), I got Fig. 17 (1,-1,1). The switch positions (S1,2,3) were correct, but the positives and negatives were swapped for S2 and S3. the values for S1 and the position of all three 0s were correct, but it seems like something may be wrong with the charts and table in the manual, or at least Fig. 2-4 and Fig. 7.
最后由 Lagmeister 编辑于; 2018 年 10 月 23 日 下午 4:38
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firestarter  [开发者] 2018 年 10 月 23 日 上午 10:44 
Hello, thank you for your comment. I checked and playtested the module, so I would be quite suprised if there was a bug.
Why is in your table [S3] [S1] [S2]? The switches (left-to-right) are always: S1,S2,S3
Did you mean to write coefficients [C3][C1][C2], meaning that wiring is [S1~C3], [S2~C1] and [S3~C2] ???
Please let me know what is confusing in the manual, I am not a native speaker.
Do you have a logfile from your gameplay? On windows, the log for modded modules is normally saved to:
C:\Program Files (x86)\Steam\steamapps\common\Keep Talking and Nobody Explodes\ktane_Data\output_log.txt

#1
Lagmeister 2018 年 10 月 23 日 下午 2:56 
Sorry I meant Coefficient. I’m using a mac btw. I’ll play test it again, but I’m pretty certain there’s something wrong with the manual or the module. Other than that though, I do like the module and it’s always fun when encountering it during gameplay
最后由 Lagmeister 编辑于; 2018 年 10 月 23 日 下午 2:59
#2
firestarter  [开发者] 2018 年 10 月 24 日 上午 1:18 
It looks like you got everything right, but you didn't take in account the switch-to-coefficient wiring, which in this case is (as you correctly determined): [S1~C3], [S2~C1], [S3~C2].

This is your table:

[S1~C3] [S2~C1] [S3~C2]
U: [-1] [ 0] [-1]
M : [ 1] [-1] [ 1]
D: [ 0] [ 1] [ 0]

You arranged the SWITCHES as follows:
(S1,S2,S3) = (M,D,U) = (1,1,-1)

So the COEFFICIENTS will be:
(C1,C2,C3) = (1,-1,1) = Fig.17 ...and that's what you got!

Btw, I'm glad you like the module :-)
And we are not spoiling anything here, the switch wiring is shuffled randmoly for every instance of the module.
最后由 firestarter 编辑于; 2018 年 10 月 24 日 上午 6:45
#3
Lagmeister 2018 年 10 月 24 日 下午 12:00 
The figure for channel A needed Fig. 15 for channel B though (Forgot to mention this. Oops)
最后由 Lagmeister 编辑于; 2018 年 10 月 24 日 下午 12:00
#4
firestarter  [开发者] 2018 年 10 月 25 日 上午 1:57 
Yes, according to Table1, Fig.17 is an incorrect solution.

* Having Fig.4 on channel A, the correct solution is Fig.15:
(C1,C2,C3)=(1,1,-1)

* When we apply switch-to-coefficient wiring:
(C1,C2,C3)=(1,1,-1)
=>
(S2,S3,S1)=(1,1,-1)

* We apply switchposition-to-value wiring;
(S2,S3,S1)=(1,1,-1)
=>
(S2,S3,S1)=(D,M,U)

* We reorder switches as they appear on the module left-to-right:
(S2,S3,S1)=(D,M,U)
=>
(S1,S2,S3)=(U,D,M)

So after arranging switches to (S1,S2,S3)=(U,D,M), you should see Fig.15 on channel B and get a solved module.
I feel there is still some misunderstanding of the module on your side...
#5
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