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报告翻译问题









Just a quick note for anyone not familiar with english naval terminology:
When the guide says “wire”, it’s not an actual cable or anything. It refers to the vertical line at 0° in your periscope view.
Also, “aft” just means the back of the ship. Sometimes you’ll see “stern” used instead.
You have to add/substract the component of the speed you travelled parallel to the target course.
For the zero bearing case, this component happens to be zero.
For the parallel case, this component happens to be your unaugmented speed.
For a general case, you have to calculate this parallel component using trigonometry. So much is clear. In this scenario, that component happens to be the your speed times the tangent of the bearing.
It should be correct for right triangles, which isn't always the case. That's why it's an approximation that works best if you're on a nearly perpendicular course.
Of course I won't rule out that I messed up the exact relation. Feel free to correct me in this case, but I won't go back and try to derive it again myself.
The bottom line is: I know the table and the method that goes with it works. But don't take it from me, take it from the SH3 community that has used this table for decades.
Just apply it in the special case 2 (parallel course). Say you measure 3 knots, which would be the difference between the two ships, then add or your own speed to get the target speed. Here you'd be finished, but according to the general formula, you also need to multiply your speed with the tangent of the bearing angle. Why?