安装 Steam
登录
|
语言
繁體中文(繁体中文)
日本語(日语)
한국어(韩语)
ไทย(泰语)
български(保加利亚语)
Čeština(捷克语)
Dansk(丹麦语)
Deutsch(德语)
English(英语)
Español-España(西班牙语 - 西班牙)
Español - Latinoamérica(西班牙语 - 拉丁美洲)
Ελληνικά(希腊语)
Français(法语)
Italiano(意大利语)
Bahasa Indonesia(印度尼西亚语)
Magyar(匈牙利语)
Nederlands(荷兰语)
Norsk(挪威语)
Polski(波兰语)
Português(葡萄牙语 - 葡萄牙)
Português-Brasil(葡萄牙语 - 巴西)
Română(罗马尼亚语)
Русский(俄语)
Suomi(芬兰语)
Svenska(瑞典语)
Türkçe(土耳其语)
Tiếng Việt(越南语)
Українська(乌克兰语)
报告翻译问题









Coatless Dante (Classic) - 1 (01)
Super Dante - 2 (02)
Sparda - 4 (04)
Super Sparda - 8 (08)
Coatless Vergil - 16 (10)
Super Vergil - 32 (20)
Corrupt Vergil - 64 (40)
Super Corrupt Vergil - 128 (80)
If you're familiar with hex editing, you know what's going on here: the byte is broken into the 8 bits, and each one controls a single costume: 1 means you have it; 0 means you don't. The simpler version is whichever costumes you want, add those numbers together; the first is decimal, and in parentheses is hexadecimal. Difficulties have a similar thing going on, but there aren't enough of them to fill a byte, so I'm not 100% on the particulars. Hope this helps for anyone looking to unlock just a single costume.
Also, great guide!
Really useful to start playing a new game in very hard or DMD for 4 players in dmc3 crimson hahaha