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(once) = xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxyxx
xa = (end) a
xb = (end) b
xc = (end) c
ya =
yb =
yc =
ba=ab
ca=ac
cb=bc
bc=.
b.=.b
a.=
ab=(return)c
ac=(return)b
.=(return)a
```
ba=ab
cb=bc
ca=ac
bc=.
b.=.b
a.=
.c=(return)true
=(return)false
```
(once)=kkkk
kka = ak
kkb = bk
kkc = ck
ka =
kb =
kc =
https://psteamcommunity.yuanyoumao.com/sharedfiles/filedetails/?id=3441284586
ab0=1ab
ab1=1abab
/1=/ab
(once)1=0bbabababbab/ag/abbabab/ab/ag/ab
baabba=abbaba
aab=(end)ba
bag/abbabab/a=abag/abbabab/aba
bab/ag/abbabab/ab/ag/=(end)bag/abbabab/abab/ag/abbabab/a
bab/ag/abbabab/ababa=b/ag/abbabab/aba
bb/ag/abbabab/ab/ag/abbabab/aba=,0
0ba=1
1ba=ba0
ba=1
This is a direct promotion of the 15-line version. I use 'ba' instead of 'a' and 'ab' instead of '+', in which case 'a=+' can be hidden in other lines. The hard part lies in deleting the last 'b' created by line 1-3. This is solved by running line 7 twice and then line 6 in the beginning(afterward line 6 and 7 appear in turn). Line 8 is always a disaster. In this program line 8 also has to make sure that the condition of line 7 is not satisfied when it is the turn for line 9 (this cost me many hours!).
a0=0aa
a1=0aaa
(once)/1=a,0g+a,0,0ga,0a
(once)1=0a
00a=0a
d=(end)a
ag+a,0=dg+a,0a
a,0g+a,0,0g=(end)g+a,0,0g+a,0
a+=+a
a,0g+a,0a=,0g+a,0
,0g+a,0,0g+a,0a=,0
a=+
0+=1
1+=+0
+=1
Comments. 'a' in 6-1, line 1-5 transform two numbers to '0aa'. '+' means add 1 to a number, line 13-15 transform '0++' to number. Line 6,7 copies divisor to end separated by 'g+a,0'. Line 9 makes sure '+' is at start. There are 3 numbers, dividend ',0g+a,0' divisor ',0g+a,0' divisor. If dividend > 0, line 10 substracts the first two numbers and goto line 8, otherwise substract the last two and goto line 11. Line 11 deletes the separate symbols. Line 12 transforms remainder from '0aa' to '0++'. Line 8 is hardest(maybe hardest in this game), means add 1 to the quotient, delete 1 separate symbol in the middle, and add 1 separate symbol at end. To do this, '+' is hidden in the separate symbol and line 8 deletes the 'g' so '+' appears.
#there are at most five c's in between a and b
ab=bb
ba=bb
acb=bcb
bca=bcb
accb=bccb
bcca=bccb
acccb=bcccb
bccca=bcccb
bcccca=bccccb
accccb=bccccb
bccccca=bcccccb
acccccb=bcccccb
a=c
aaaaaaaab=baaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaa=trueb
baaaaaaaaaaaaaaaaaaaaaaaa=
aaaaaaaaa=
ea=eaaaaaaaa
atrueb=truebaaaaaaaa
truetrueb=false
eb=eaaaaaaaaaaaaaaaaaaaaaaaa
c=baaaaaab
b=trueb
aa=true
(once)=(end)||||||||||||||||||||||||||||||||||||||||||||||||||||c|c||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
a|=(start)a
b|=(start)b
(once)bc|c||=(start)acc
(once)cc|c||=bc|c||
c|=(start)c
(once)acc=